Further Mathematics
AI prompts for senior secondary learners.
📅 36-Week WAEC Study Guide for Further Mathematics →790 prompts matching "Solve 4x^2 - 12x + 5 = 0 with full exam working"
Showing only prompts that state their year. 35 more in this subject don't name one, so choose All years to see them.
Worked example: solve x^2+4x+13=0 giving the roots as complex numbers
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Subscribe to unlock allWorked example: solving an equation with logarithms to the same base
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Subscribe to unlock allWorked example: an AP with first term 5 and common difference 3, find the 20th term and the sum of the first 20 terms
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Subscribe to unlock allWorked example: a GP with first term 4 and common ratio 2, find the 8th term and the sum of the first 8 terms
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Subscribe to unlock allWorked example: a GP with first term 100 and common ratio 0.5, find the sum to infinity
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Subscribe to unlock allWorked example: find the gradient of y = x^3 - 4x at the point where x = 2
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Subscribe to unlock allWorked example: find the equation of a circle with centre (2,-1) and radius 4
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Subscribe to unlock allWorked example: use matrices to solve the simultaneous equations 2x+y=8 and x-y=1
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Subscribe to unlock allShow All Working: Completing the square with a fractional coefficient of x
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Subscribe to unlock allShow All Working: Factorising a polynomial with fractional roots
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Subscribe to unlock allShow All Working: A circular arrangement with one fixed seat such as the head
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Subscribe to unlock allShow All Working: Selecting a committee with the chairman named separately
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Subscribe to unlock allWorked Example: Counting the total outcomes with combinations
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Subscribe to unlock allIGCSE Additional Maths Y11: Solving an equation within a stated range of radians — Worked Example
I am a Year 11 pupil taking Cambridge IGCSE Additional Mathematics. Take me through one co
Subscribe to unlock allWorked example: applying predicate logic to solve a problem
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Subscribe to unlock allWorked example: expand (x+2)^5 fully using the binomial theorem
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Subscribe to unlock allWorked example: expand (1-x)^4 fully and use it to estimate (0.98)^4
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