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Further Mathematics

AI prompts for senior secondary learners.

📅 36-Week WAEC Study Guide for Further Mathematics →
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755 prompts matching "WAEC-style question on evaluating composite functions"

Showing only prompts that state their year. 35 more in this subject don't name one, so choose All years to see them.

Spot My Mistake: A logarithm to base e, the natural logarithm

Act as my SS1 Further Mathematics tutor. Work a question on a logarithm to base e, the nat

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Show All Working: Comparing logarithms given in different bases

Act as my Further Mathematics examiner. I am in SS 1. Set me a question on comparing logar

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Learn: What a sequence is, and what a term means

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Worked Example: Writing out the terms of a sequence from its nth term

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Quiz: Finding the nth term of a linear sequence

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Practice: Finding the nth term of a quadratic sequence

Act as my SS1 Further Mathematics tutor. Give me five practice questions on finding the nt

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Explain Back: Spotting the pattern in a sequence of squares or cubes

I have just studied spotting the pattern in a sequence of squares or cubes in my SS1 Furth

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Show All Working: Deciding whether a given number is a term of a sequence

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Explain Back: Finding the first term from two given terms

I have just studied finding the first term from two given terms in my SS1 Further Mathemat

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Worked Example: The alternative sum formula that uses the last term

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Quiz: The sum of the first fifty natural numbers

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Quiz: Multiplying both sides by a positive number

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Practice: Reversing the sign when multiplying by a negative number

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Learn: Factorising a quadratic before solving the inequality

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Worked Example: The critical values of a quadratic inequality

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Practice: Using a table of signs to solve a quadratic inequality

Act as my SS1 Further Mathematics tutor. Give me five practice questions on using a table

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Learn: What the modulus of a number means

You are my personal SS1 Further Mathematics tutor. Teach me what the modulus of a number m

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Quiz: Solving modulus of x less than a

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Practice: Solving modulus of x greater than a

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Explain Back: Solving an inequality such as modulus of 2x minus 1 less than 5

I have just studied solving an inequality such as modulus of 2x minus 1 less than 5 in my

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