Further Mathematics
AI prompts for senior secondary learners.
π 36-Week WAEC Study Guide for Further Mathematics β755 prompts matching "Teach me the universal and existential quantifiers"
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IGCSE Additional Maths Y10: Exponential decay in a real situation β Common Mistakes
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Subscribe to unlock allIGCSE Additional Maths Y10: Reading a value off an exponential graph β Exam Technique
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Subscribe to unlock allIGCSE Additional Maths Y10: A growth or decay problem solved with natural logarithms β Show All Working
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Subscribe to unlock allIGCSE Additional Maths Y10: Checking an answer involving e to three significant figures β Exam Technique
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Subscribe to unlock allIGCSE Additional Maths Y10: Choosing what to plot on each axis β Practice Set
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Subscribe to unlock allIGCSE Additional Maths Y10: Converting a table of values to logarithms before plotting β Spot My Mistake
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Subscribe to unlock allIGCSE Additional Maths Y10: Sketching a straight line from its equation using both intercepts β Exam Technique
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Subscribe to unlock allIGCSE Additional Maths Y10: Showing that two given lines are perpendicular β Spot My Mistake
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Subscribe to unlock allIGCSE Additional Maths Y10: Proving that a triangle is right-angled using gradients β Exam Technique
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Subscribe to unlock allIGCSE Additional Maths Y10: Showing that three points are collinear β IGCSE Exam Practice
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Subscribe to unlock allIGCSE Additional Maths Y10: Rearranging an equation so that a drawn curve can solve it β Explain It Back
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Subscribe to unlock allIGCSE Additional Maths Y10: Estimating a root to one decimal place from a graph β IGCSE Exam Practice
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Subscribe to unlock allIGCSE Additional Maths Y10: Solving an inequality graphically β Show All Working
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Subscribe to unlock allIGCSE Additional Maths Y10: How accurate a graphical solution really is β Common Mistakes
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Subscribe to unlock allIGCSE Additional Maths Y10: Checking a graphical solution by substitution β Exam Technique
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Subscribe to unlock allWorked Example: What makes two surds equal
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Subscribe to unlock allExplain Back: Multiplying root a by root b
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