Further Mathematics
AI prompts for senior secondary learners.
📅 36-Week WAEC Study Guide for Further Mathematics →1,332 prompts matching "Finding the first term from the sum and the common difference"
Showing only prompts that state their year. 35 more in this subject don't name one, so choose All years to see them.
WAEC Prep: Solving a quadratic whose discriminant is negative
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Subscribe to unlock allWAEC Prep: Differentiating a polynomial with a fractional index
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Subscribe to unlock allLearn: Differentiating sin of a multiple of x
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Subscribe to unlock allWAEC Prep: Why integration undoes differentiation
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Subscribe to unlock allWAEC Prep: Integrating a polynomial divided by x
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Subscribe to unlock allWAEC Prep: Integrating a power of x
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Subscribe to unlock allWAEC Prep: Evaluating a definite integral between two limits
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Subscribe to unlock allWAEC Prep: A small percentage change estimated by calculus
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Subscribe to unlock allWAEC Prep: A body decelerating to rest
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Subscribe to unlock allWAEC Prep: Two bodies that coalesce on impact
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Subscribe to unlock allWAEC Prep: A body pulled along a rough horizontal plane
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Subscribe to unlock allLearn: Newton's second law written as F equals ma
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Subscribe to unlock allWAEC Prep: Substituting a convenient value to find one constant
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Subscribe to unlock allWAEC Prep: Splitting a fraction with two distinct linear factors
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Subscribe to unlock allSpot My Mistake: Partial fractions with an irreducible quadratic factor
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Subscribe to unlock allWAEC Prep: Dividing a polynomial by a linear divisor by long division
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Subscribe to unlock allWAEC Prep: Using a regression line to estimate a value
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Subscribe to unlock allAdd two matrices, 2x2 #1
Give me a matrix problem where A=[[2,3],[1,4]], B=[[5,-1],[0,2]] and I have to add them, s
Subscribe to unlock allSubtract two matrices, 2x2 #2
I am in SS 3. Give me a matrix problem where A=[[1,-2],[3,0]], B=[[4,1],[-2,5]] and I have
Subscribe to unlock allAdd two matrices, 2x2 #3
I am in SS 3. Give me a matrix problem where A=[[6,2],[-3,1]], B=[[1,4],[2,-5]] and I have
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