Further Mathematics
AI prompts for senior secondary learners.
📅 36-Week WAEC Study Guide for Further Mathematics →1,324 prompts matching "Finding a coefficient when the remainder is given"
Showing only prompts that state their year. 35 more in this subject don't name one, so choose All years to see them.
Explain-back: normal distribution properties
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Subscribe to unlock allSpot my mistake in a Cramer's rule solution
I am in SS 3. I solved a pair of simultaneous equations using Cramer's rule but I'm not su
Subscribe to unlock allSpot my mistake integrating a polynomial
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Subscribe to unlock allTeach me how to find the writing the inverse of a two by two matrix with the adjugate
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Subscribe to unlock allLearn: The union of two sets written in set-builder notation
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Subscribe to unlock allQuiz: The complement of a set within a stated universal set
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Subscribe to unlock allWAEC Prep: The number of elements in the union of two sets
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Subscribe to unlock allCommon Mistakes: Showing that intersection distributes over union
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Subscribe to unlock allCommon Mistakes: A binary operation defined by arithmetic modulo n
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Subscribe to unlock allLearn: Simplifying a surd by extracting the largest perfect square
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Subscribe to unlock allQuiz: Multiplying two surds and simplifying the result
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Subscribe to unlock allSpot My Mistake: Squaring a bracket that contains a surd
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Subscribe to unlock allWAEC Prep: Comparing the sizes of two surds without a calculator
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Subscribe to unlock allShow All Working: Expressing a number in the form a root b
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Subscribe to unlock allFinal Revision: Proving that root 2 is irrational
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Subscribe to unlock allQuiz: Solving an index equation by writing both sides to the same base
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Subscribe to unlock allWAEC Prep: The change of base formula for logarithms
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Subscribe to unlock allShow All Working: Solving a logarithmic equation and rejecting the invalid root
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Subscribe to unlock allCommon Mistakes: Solving an exponential equation using logarithms
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Subscribe to unlock allWAEC Prep: Forming an equation whose roots are each two more than the original
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