Further Mathematics
AI prompts for senior secondary learners.
📅 36-Week WAEC Study Guide for Further Mathematics →1,318 prompts matching "IGCSE Additional Maths Y10: The solution set when the two roots are equal — Spot"
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Worked example: finding the argument in the correct quadrant
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Subscribe to unlock allSpot My Mistake: De Morgan's law that the complement of a union is the intersection of the complements
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Subscribe to unlock allShow All Working: A three-set Venn diagram drawn from a subject survey
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Subscribe to unlock allSpot My Mistake: Finding the inverse of an element under a binary operation
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Subscribe to unlock allWAEC Prep: Completing a Cayley table for an operation on a small set
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Subscribe to unlock allQuiz: Multiplying two surds and simplifying the result
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Subscribe to unlock allWAEC Prep: Comparing the sizes of two surds without a calculator
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Subscribe to unlock allShow All Working: Expressing a number in the form a root b
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Subscribe to unlock allCommon Mistakes: Solving an equation in which the unknown sits under a root
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Subscribe to unlock allQuiz: Solving an index equation by writing both sides to the same base
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Subscribe to unlock allSpot My Mistake: The power law of logarithms
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Subscribe to unlock allWAEC Prep: The change of base formula for logarithms
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Subscribe to unlock allShow All Working: Solving a logarithmic equation and rejecting the invalid root
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Subscribe to unlock allWorked Example: The discriminant, and what each of its three cases means
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Subscribe to unlock allSpot My Mistake: Forming a new equation whose roots are the reciprocals of the original
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Subscribe to unlock allWAEC Prep: Forming an equation whose roots are each two more than the original
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Subscribe to unlock allShow All Working: Solving a quadratic by completing the square
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Subscribe to unlock allShow All Working: Finding a coefficient given a stated relation between the roots
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Subscribe to unlock allQuiz: The factor theorem, and testing whether x minus a is a factor
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Subscribe to unlock allSpot My Mistake: The factor theorem for a divisor of the form ax minus b
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