Further Mathematics
AI prompts for senior secondary learners.
📅 36-Week WAEC Study Guide for Further Mathematics →755 prompts matching "Practice: Solving an inequality with the unknown in the denominator"
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Common Mistakes: An arithmetic progression with a negative common difference
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Subscribe to unlock allFinal Revision: Inserting an arithmetic mean between two numbers
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Subscribe to unlock allLearn: The formula for the sum of the first n terms of an arithmetic progression
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Subscribe to unlock allWAEC Prep: A word problem about seats in the rows of a hall
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Subscribe to unlock allFinal Revision: A savings problem modelled by an arithmetic progression
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Subscribe to unlock allShow All Working: A geometric progression with a fractional common ratio
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Subscribe to unlock allFinal Revision: Deciding whether a given sequence is a geometric progression
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Subscribe to unlock allFinal Revision: Proving the sum formula for a geometric progression
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Subscribe to unlock allQuiz: Using a sketch of the parabola to read off the solution
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Subscribe to unlock allSpot My Mistake: The solution when the quadratic expression is less than nought
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Subscribe to unlock allLearn: What the modulus of a number means
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Subscribe to unlock allFinal Revision: Writing the inequalities that describe a shaded region
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Subscribe to unlock allIGCSE Additional Maths Y10: The range of a function — Quiz Me
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Subscribe to unlock allIGCSE Additional Maths Y10: Interval notation for a range — Spot My Mistake
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Subscribe to unlock allIGCSE Additional Maths Y10: Forming the composite function fg — Quiz Me
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Subscribe to unlock allIGCSE Additional Maths Y10: Finding the inverse of a linear function — Spot My Mistake
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Subscribe to unlock allIGCSE Additional Maths Y10: Solving f of x equals f inverse of x — Exam Technique
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Subscribe to unlock allIGCSE Additional Maths Y10: The graph of a one-one function — Practice Set
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Subscribe to unlock allIGCSE Additional Maths Y10: Finding an inverse graphically — Spot My Mistake
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Subscribe to unlock allIGCSE Additional Maths Y10: Solving a modulus equation algebraically by squaring — Explain It Back
I am in SS 1. I have just studied solving a modulus equation algebraically by squaring for
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