Further Mathematics
AI prompts for senior secondary learners.
📅 36-Week WAEC Study Guide for Further Mathematics →434 prompts matching "Quiz: Forming a quadratic equation whose roots are given"
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Spot My Mistake: Finding a missing coefficient from a stated product of roots
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Subscribe to unlock allWAEC Prep: Checking the sum and product against the solved roots
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Subscribe to unlock allShow All Working: Roots equal in magnitude but opposite in sign
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Subscribe to unlock allFinal Revision: One root twice the other, and what that gives
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Subscribe to unlock allWorked Example: The identity linking alpha squared plus beta squared to the sum and product
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Subscribe to unlock allExplain Back: The value of alpha minus beta, all squared
I have just studied the value of alpha minus beta, all squared in my SS2 Further Mathemati
Subscribe to unlock allWorked Example: Substituting into the quadratic and tidying up
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Subscribe to unlock allSpot My Mistake: A pair with equal roots, meaning one solution only
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Subscribe to unlock allShow All Working: A simultaneous pair in which the second equation is a circle
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Subscribe to unlock allFinal Revision: Checking both solutions in both equations
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Subscribe to unlock allQuiz: The condition for two points of intersection
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Subscribe to unlock allQuiz: The leading term and the constant term
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Subscribe to unlock allExplain Back: Evaluating P of 2 for a given polynomial
I have just studied evaluating P of 2 for a given polynomial in my SS2 Further Mathematics
Subscribe to unlock allWAEC Prep: Expressions that are not polynomials, and why not
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Subscribe to unlock allQuiz: The remainder on dividing by x plus 2
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Subscribe to unlock allExplain Back: Finding a coefficient when the remainder is given
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Subscribe to unlock allPractice: Showing that x plus 3 is a factor of a given polynomial
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Subscribe to unlock allShow All Working: What the factor theorem says about the roots
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Subscribe to unlock allWorked Example: Factorising a cubic into a linear and a quadratic factor
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Subscribe to unlock allQuiz: Factorising a polynomial by grouping terms
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