Mathematics
AI prompts for junior secondary learners.
📝 3 Mathematics practice tests with answers →797 prompts matching "Working out a finishing time from a start time and a duration"
Showing only prompts that state their year. 3 more in this subject don't name one, so choose All years to see them.
Learn: Substituting a value into a simple algebraic expression
I'm a JSS2 student and I don't fully understand substituting a value into a simple algebra
Subscribe to unlock allTest My Knowledge of Simple Equations
Give me a short 5-question quiz on simple equations covering solving a simple linear equat
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Subscribe to unlock allExam Prep: Simple Equations Key Points
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Subscribe to unlock allMore Practice: Which transformations keep a shape the same size
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Subscribe to unlock allLearn: Finding the sum of the angles of a triangle
I'm a JSS2 student and I don't fully understand finding the sum of the angles of a triangl
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Subscribe to unlock allCompare Methods: Finding several missing angles in one polygon
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Subscribe to unlock allPractice Questions: The two equal angles of an isosceles triangle in a diagram
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Subscribe to unlock allSpot My Mistake: Proving the angle sum of a triangle using parallel lines
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Subscribe to unlock allMore Practice: Why the exterior angles of any polygon add to 360 degrees
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Subscribe to unlock allSpot My Mistake: Choosing the scale before drawing an elevation diagram
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Subscribe to unlock allSpot My Mistake: The plan view of a cone compared with its elevation
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Subscribe to unlock allExplain Bearing Back to My Tutor
Let me explain giving a bearing as a three-figure bearing in bearing back to you in my own
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Give me a short 5-question quiz on bearing covering giving a bearing as a three-figure bea
Subscribe to unlock allExplain Pythagoras' Theorem Back to My Tutor
Let me explain recognising a Pythagorean triple such as 3, 4, 5 in pythagoras' theorem bac
Subscribe to unlock allLearn: Recognising a Pythagorean triple such as 3, 4, 5
I'm a JSS2 student and I don't fully understand recognising a Pythagorean triple such as 3
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